Let ð‘“(ð‘¥) = 1/ð‘¥. We apply the following transformations to ð‘“(ð‘¥) consecutively to obtain g(x): Shift to the left by 2. Reflect with respect to the ð‘¥-axis. Shift upward by 3.
Added by Edward S.
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So, the new function becomes: f(x+2) = 1/(x+2) Show more…
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