Let G be a group. Prove that, for g ∈ G, there is a unique element g^−1 such that gg^−1 = g^−1g = 1G. That is, prove that inverse elements are unique.
Added by Jacqueline M.
Your feedback will help us improve your experience
Sri K and 74 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Prove that the inverse of an element in a group is unique.
Sri K.
Let G be an abelian group. If H = {x ∈ G | x = x^-1}, that is, H consists of all the elements of G which are their own inverses, prove that H is a subgroup of G.
Adi S.
Let $G$ be an abelian group. If $H=\left\{x \in G: x=x^{-1}\right\}$, that is, $H$ consists of all the elements of $G$ which are their own inverses, prove that $H$ is a subgroup of $G$.
SUBGROUPS
C
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD