00:01
For this problem, we are told to let t not be a specific value of t.
00:04
We're asked to use a use technology or table three from appendix b to find t not values such that the following statements are true.
00:13
Now, i'll copy in the table that we'll be using.
00:19
So we have in part a probability that t is between plus and minus negative or plus or minus t not equals 0 .95, where df equals 19.
00:30
Now we'd have that alpha is going to be equal to 0 .05, and we are going to want to look for alpha over 2, which equals 0 .0025, or excuse me, 0 .025.
00:43
So we want to use this column, and we want to go down to the row corresponding to 19 degrees of freedom.
00:50
So intersecting the two, we can find that in part a, the answer is t equals 2 .093.
00:59
Then for part b, we have that t is less than or equal to t not equals 0 .01, or df equals 6.
01:09
So we want this column and this row.
01:16
So let's see here, 3 .143...