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Let X have a binomial distribution with parameters n 25 and p. Calculate each of the following probabilities using the normal approximation (with the continuity correction) for the cases p 0.5, 0.6, and 0.8 and compare to the exact binomial probabilities calculated directly from the formula for b(x; n,p). (Round your answers to four decimal places.) (a) P(15 s X s 20) p P(15 X 20) P(14.5 Normal s 20.5) 0.5 0.6 0.8 The normal approximation of P/15 s xs 20) for p 0.5 is Select the exact probability of P(15 s xs 20) for p o.5 The normal approximation of P(15 X 20) for: 0.6 is!--Select… ? the exact probability of P(15 X 20) for p = 0.6. The normal approximation of p(15 S XS 20) for: 0.8 is -Select-- ? the exact probability of p (15 S X S 20) for p-0.8. (b) P(X S 15) p P(Xs15) P(Normal s 15.5) 0.5 0.6 0.8 The normal approximation of P(X S 15) for p 0.5 is Select the exact probability of P(X S 15) for p0.5 The normal approximation of P(X 15) for p = 0.6 is | Select-. ? the exact probability of P(X 15) for ? = 0.6 The normal approximation of P(X 15) for p0.8 is Slthe exact probability of P X S 15) for p 0.8. p P(20 X) P(19.5 Normal) 0.5

Name: let x have a binomial distribution with parameters n 25 and p calculate each of the following probabilities using the normal approximation with the continuity correction for the cases p 05 0 34014
Uploaded: 2024-07-11T03:53:38-08:00
Duration: 1 min 37 s
Channel: Adi S
Description: let x have a binomial distribution with parameters n 25 and p calculate each of the following probabilities using the normal approximation with the continuity correction for the cases p 05 0 34014

          Let X have a binomial distribution with parameters n 25 and p. Calculate each of the following probabilities using the normal approximation (with the continuity correction) for the cases p 0.5, 0.6, and 0.8 and compare to the exact binomial probabilities calculated directly from the formula for b(x; n,p). (Round your answers to four decimal places.) (a) P(15 s X s 20) p P(15 X 20) P(14.5 Normal s 20.5) 0.5 0.6 0.8 The normal approximation of P/15 s xs 20) for p 0.5 is Select the exact probability of P(15 s xs 20) for p o.5 The normal approximation of P(15 X 20) for: 0.6 is!--Select… ? the exact probability of P(15 X 20) for p = 0.6. The normal approximation of p(15 S XS 20) for: 0.8 is -Select-- ? the exact probability of p (15 S X S 20) for p-0.8. (b) P(X S 15) p P(Xs15) P(Normal s 15.5) 0.5 0.6 0.8 The normal approximation of P(X S 15) for p 0.5 is Select the exact probability of P(X S 15) for p0.5 The normal approximation of P(X 15) for p = 0.6 is | Select-. ? the exact probability of P(X 15) for ? = 0.6 The normal approximation of P(X 15) for p0.8 is Slthe exact probability of P X S 15) for p 0.8. p P(20 X) P(19.5 Normal) 0.5

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