$\lim_{x\to 0} \left(\frac{\sin(2x)}{2x}\right) = 1$ Show that using geometry information. (Do not use L'HĂ´pital's Rule.)
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Dividing both the numerator and denominator by 6x, we get: (6x)/(6x^2) = (x)/(x^2) Now, we can rewrite the expression as: (x)/(x^2) = 1/(x) As x approaches 0, the denominator becomes smaller and smaller, approaching infinity. Show more…
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