Question

loga(x - y) = p and loga(x + y) = k What is $x^2 - y^2$? a. P+k b. $a^{p+k}$ c. $a^{p-k}$ d. $a^{p/k}$

          loga(x - y) = p and loga(x + y) = k What is $x^2 - y^2$?
a. P+k
b. $a^{p+k}$
c. $a^{p-k}$
d. $a^{p/k}$

Added by Brittany R.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Ben Blakesley

Step 1

From the first equation, we have logâ‚(x - y) = p. This can be rewritten as 10^p = x - y. From the second equation, we have logâ‚(x + y) = k. This can be rewritten as 10^k = x + y. Now, let's add the two equations together: 10^p + 10^k = (x - y) + (x + Show more…

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