00:01
Alright, so for a, if we're talking about a multiple of 4, it means that that number can be divided evenly by 4 without a new remainder.
00:09
So let's see that that number is 4n, where n is any integer.
00:13
Now let's consider a multiple of that number.
00:16
So let's say 4n times m, where m is also an integer.
00:20
Using our bunch of sets of 4 idea, we can think of the original number as a bunch of sets of 4 with nothing left over, and when we multiply it by another integer, we are essentially adding more sets to the bunch.
00:35
Since each set of 4 is divisible by 4, adding more sets of 4 will still result in a number that is divisible.
00:42
Therefore, any multiple of 4 is also going to be a multiple.
00:52
For example, for b, i would say that this is false...