Question

Many chemistry problems result in equations of the form $2.00 \times 10^{-2} = \frac{x^2}{(0.216 - x)}$ When this equation is solved, the two values of the unknown $x$ are and .

          Many chemistry problems result in equations of the form
$2.00 \times 10^{-2} = \frac{x^2}{(0.216 - x)}$
When this equation is solved, the two values of the unknown $x$ are ______ and ______.

Many chemistry problems result in equations of the form
2.00 × 10^-2 = (x^2)/((0.216 - x))
When this equation is solved, the two values of the unknown x are and .

Added by Francisco R.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Nathan Smith

Step 1

00 x 10^-2 = x^2/(0.216 - x). Multiply both sides by (0.216 - x) to clear the denominator: 2.00 x 10^-2 (0.216 - x) = x^2 Show more…

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Many chemistry problems result in equations of the form 2.00 x 10^-2 = x^2 (0.216 - x) When this equation is solved, the two values of the unknown x are and