Exercise 5.8 Show that the total internal energy in the mean field theory is $\langle E \rangle = -N\mu H m - (1/2)JNzm^2$. At $H = 0$ and $T = 0$, this gives $\langle E \rangle = -NDJ$, in agree- ment with the exact result. What does the theory predict for $T > T_c$? Is the prediction correct?
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The mean field theory equation you provided is: E = -NuHm - 1/2JNzm^2 where: - E is the energy of the system - Nu is the number of nearest neighbors - Hm is the magnetic field - J is the exchange interaction strength - N is the total number of spins - zm is the Show more…
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