Question

h. If we increase the side of the square from 3.5 cm to 6 cm the square's perimeter i. Determine the value of $\Delta P$ as $s$ increases from 3.5 cm to 6 cm. $\Delta P =$ j. As the value $s$ and $P$ vary together in the relationship where $P = 4s$, define $\Delta P$ in terms of $\Delta s$. k. Which of the following describes a relationship defined by the formula $P = 4s$? Submit Since $s$ and $P$ are proportional, $P$ varies at a constant rate of change with respect to $s$. For any change in $s$, $\Delta s$, away from a point ($s_1, P_1$) in the relationship, $\Delta P = 4\Delta s$. Given any two points in the relationship ($s_1, P_1$) and ($s_2, P_2$), $\frac{P_2 - P_1}{s_2 - s_1} = 4$. Given any point ($s, P$) in the relationship, $P$ is always 4 times as large as $s$ The point (6, 24) in the relationship conveys that $24 = 4(6)$. Question 8. Points possible: 3 Unlimited attempts. Message instructor about this question Post this question to forum

          h. If we increase the side of the square from 3.5 cm to 6 cm the square's perimeter
i. Determine the value of $\Delta P$ as $s$ increases from 3.5 cm to 6 cm.
$\Delta P =$
j. As the value $s$ and $P$ vary together in the relationship where $P = 4s$, define $\Delta P$ in terms of $\Delta s$.
k. Which of the following describes a relationship defined by the formula $P = 4s$?
Submit
Since $s$ and $P$ are proportional, $P$ varies at a constant rate of change with respect to $s$.
For any change in $s$, $\Delta s$, away from a point ($s_1, P_1$) in the relationship, $\Delta P = 4\Delta s$.
Given any two points in the relationship ($s_1, P_1$) and ($s_2, P_2$), $\frac{P_2 - P_1}{s_2 - s_1} = 4$.
Given any point ($s, P$) in the relationship, $P$ is always 4 times as large as $s$
The point (6, 24) in the relationship conveys that $24 = 4(6)$.
Question 8. Points possible: 3
Unlimited attempts.
Message instructor about this question
Post this question to forum

h. If we increase the side of the square from 3.5 cm to 6 cm the square's perimeter
i. Determine the value of Δ P as s increases from 3.5 cm to 6 cm.
Δ P =
j. As the value s and P vary together in the relationship where P = 4s, define Δ P in terms of Δ s.
k. Which of the following describes a relationship defined by the formula P = 4s?
Submit
Since s and P are proportional, P varies at a constant rate of change with respect to s.
For any change in s, Δ s, away from a point (s1, P1) in the relationship, Δ P = 4Δ s.
Given any two points in the relationship (s1, P1) and (s2, P2), (P2 - P1)/(s2 - s1) = 4.
Given any point (s, P) in the relationship, P is always 4 times as large as s
The point (6, 24) in the relationship conveys that 24 = 4(6).
Question 8. Points possible: 3
Unlimited attempts.
Message instructor about this question
Post this question to forum

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