n = 118, X = 45, p' = 0.3814. How many additional students must you sample for the error bound to be half its size? Do this for c = 0.95. Keep t-score or z-score the same as part d. Show all steps.
Added by Michael J.
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3814, and c = 0.95, we can use a Z-score of 1.96 for a 95% confidence level. Margin of Error = 1.96 * sqrt((0.3814*(1-0.3814)) / 118) Margin of Error ≈ 0.079 Show more…
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