Question

n = 49; sample mean = 54.8; $\sigma$ = 28 H$_0$: $\mu$ = 50; H$_a$: $\mu \neq$ 50 a. Compute the test statistic. 1.2 b. What's the rejection rule? Reject H$_0$ if $|z| > z_{\alpha/2}$ c. At the .05 level of significance, your Critical Value is 1.96 d. If the test is done at a 5% level of significance, the null hypothesis should be reject

Name: n 49 sample mean 548 sigma 28 h0 mu 50 ha mu neq 50 a compute the test statistic 12 b whats the rejection rule reject h0 if z zalpha2 c at the 05 level of significance your critical valu 91924
Uploaded: 2022-05-25T19:20:20-08:00
Duration: 2 min 56 s
Channel: David Nguyen
Description: n 49 sample mean 548 sigma 28 h0 mu 50 ha mu neq 50 a compute the test statistic 12 b whats the rejection rule reject h0 if z zalpha2 c at the 05 level of significance your critical valu 91924

          n = 49; sample mean = 54.8; $\sigma$ = 28
H$_0$: $\mu$ = 50; H$_a$: $\mu \neq$ 50

a. Compute the test statistic. 1.2

b. What's the rejection rule? Reject H$_0$ if $|z| > z_{\alpha/2}$

c. At the .05 level of significance, your Critical Value is 1.96

d. If the test is done at a 5% level of significance, the null hypothesis should be reject

n 49 sample mean 548 sigma 28 h0 mu 50 ha mu neq 50 a compute the test statistic 12 b whats the rejection rule reject h0 if z zalpha2 c at the 05 level of significance your critical valu 91924

Added by Jerry T.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert David Nguyen

05/25/2022

Step 1

Given information: Sample size, n = 49 Sample mean, $\bar{x}$ = 54.8 Population standard deviation, $\sigma$ = 28 Null hypothesis, H$_0$: $\mu$ = 50 Alternative hypothesis, H$_a$: $\mu \neq$ 50 Level of significance, $\alpha$ = 0.05 Part a: Compute the test Show more…

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n = 49; sample mean = 54.8; $\sigma$ = 28 H$_0$: $\mu$ = 50; H$_a$: $\mu \neq$ 50 a. Compute the test statistic. 1.2 b. What's the rejection rule? Reject H$_0$ if $|z| > z_{\alpha/2}$ c. At the .05 level of significance, your Critical Value is 1.96 d. If the test is done at a 5% level of significance, the null hypothesis should be reject