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1. (Jupyter) Consider the function $f(x) = \frac{1}{2}x^2$. Write a simple Python program to optimize this objective function with gradient descent. Show that the function is a minimum at $x^* = 0$. 2. (Jupyter) Generate N data points \{$(y_i, x_i)$\} where $y = mx + b$ and add Gaussian noise. (a) Plot the data. (b) Fit a linear model and print the coefficients $m$ and $b$. (c) Plot the optimal model together with the data.

          1. (Jupyter) Consider the function $f(x) = \frac{1}{2}x^2$. Write a simple Python program to optimize this objective function with gradient descent. Show that the function is a minimum at $x^* = 0$.
2. (Jupyter) Generate N data points \{$(y_i, x_i)$\} where $y = mx + b$ and add Gaussian noise. (a) Plot the data. (b) Fit a linear model and print the coefficients $m$ and $b$. (c) Plot the optimal model together with the data.
        
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1. (Jupyter) Consider the function f(x) = (1)/(2)x^2. Write a simple Python program to optimize this objective function with gradient descent. Show that the function is a minimum at x^* = 0.
2. (Jupyter) Generate N data points {(yi, xi)} where y = mx + b and add Gaussian noise. (a) Plot the data. (b) Fit a linear model and print the coefficients m and b. (c) Plot the optimal model together with the data.

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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Jupyter Consider the function f = Write a simple Python program to optimize this objective function with gradient descent. Show that the function is a minimum at *0. 2. Jupyter Generate N data points {y} where y = mx + b and add Gaussian noise. a) Plot the data. b) Fit a linear model and print the coefficients m and b. c) Plot the optimal model together with the data.
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00:01 Ok, quindi abbiamo la nostra base b fatta da questi tre vectori b1 che è il vectore 0, negativo 1, negativo 1 v2 che è il vectore negativo 4, 0, 0 e v3 il vectore 6, 6, 3 perfetto ora, le coordinate di x in questa base b sono negativo 2, 6 oh, questo è negativo 2 quindi negativo 2, 6 e 1 quindi questo significa che x può essere scritto come negativo 2 moltiplicato da v1 più 6 moltiplicato da v2 più 1…
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