00:01
Here we are asked to balance the equation.
00:03
Here nh3 plus cl2 is given to us.
00:08
That gives you nh4cl plus n2 here.
00:15
Isn't it? so let's look on to the first one, first equation, first part on the left hand side.
00:25
So, only you could see here cl is present on the left hand side only in one molecule, right? and on the right hand side also the same it is present, okay? so, now you can write here 2nh4cl, right? first of all, right? now cl2 is balanced now, right? right.
00:54
Now, how many h are there now? four twos are eight.
00:59
So h is eight atoms here.
01:02
Eight atoms now.
01:03
Right.
01:04
Because cl is balanced.
01:06
Cl is actually balanced.
01:09
Okay.
01:10
So h has eight atoms and n, how many n atoms are there? there would be 2n, 2 plus 2 which is equals to 4, right? 4 atoms are there.
01:30
Perfect.
01:31
Now here you could see 3 atoms are here for h, right? and for n it is 1 atom.
01:43
So first of all you need to balance h atom, right? right.
01:57
So how is it possible? we want eight atoms here.
02:06
So it would be eight divided by three.
02:09
So that would give you eight divided by three multiplied by three...