Question

0 w k mg k 1. Consider the spring loaded pendulum shown above. Assume that the spring force acting on the pendulum is zero when the pendulum is vertical ($\theta = 0$). Assume that $\theta$ is small, so $\sin\theta \approx \theta$ and $\cos\theta \approx 1$. Also note that for small $\theta$, the spring force is approximately horizontal. Obtain the state variable representation of the system if $x_1$ is the angular position and $x_2$ is the angular velocity of the pendulum.

          0
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1. Consider the spring loaded pendulum shown above. Assume that the spring force acting on the
pendulum is zero when the pendulum is vertical ($\theta = 0$). Assume that $\theta$ is small, so $\sin\theta \approx \theta$ and
$\cos\theta \approx 1$. Also note that for small $\theta$, the spring force is approximately horizontal. Obtain the state
variable representation of the system if $x_1$ is the angular position and $x_2$ is the angular velocity of the
pendulum.
        
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0
w
k
mg
k
1. Consider the spring loaded pendulum shown above. Assume that the spring force acting on the
pendulum is zero when the pendulum is vertical (θ = 0). Assume that θ is small, so sinθ≈θ and
cosθ≈ 1. Also note that for small θ, the spring force is approximately horizontal. Obtain the state
variable representation of the system if x1 is the angular position and x2 is the angular velocity of the
pendulum.

Added by Thomas R.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Pendulum. Variable representation of the system if θ is the angular position and ω is the angular velocity of the cosθ. Also note that for small θ, the spring force is approximately horizontal. Obtain the state WMM.
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Transcript

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00:02 In the first part of this problem, we have to show that the force acting on pendulum is same as the force in the hooks law.
00:08 So we have to show that the force acting on pendulum that is proportional to the displacement, that is x.
00:16 And this force is directed towards the main position.
00:21 So we have to show this relation for the case of simple pandolin.
00:25 Let's draw the simple pendulum first.
00:29 So this is the simple pendulum, whose component of force mg sine fendulum.
00:35 Is responsible to execute the simple harmonic motion and this force is directed towards the mean position which is represented by this o.
00:44 So we can write here this force f should be equals to minus mg sign of theta.
00:53 Now using the small angle approximation which is a sign of theta is approximately equals to theta when theta is very small then this square will be f is equal to minus m g theta now taking this this a say this is a oh a and say this is c as a semicircle we can write here an expression for the this circumference which is represented by this x as a theta is equals to x divided by and where this l is the length of the pendulum then this equation will be f is equal to minus m g x divided by l so this can be further written as minus into mg divided by l into x we know that this is mg divided by l this is the constant so we can white f is proportional to minus x so this is the form of the hook slah which is also applicable for the simple pandolo and proved...
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