00:01
So, in question number 1, given q1 equal to 3 micro coulomb which is equal to 3 multiplied by 10 raised to power minus 6 coulombs and q2 equal to 3 micro coulombs.
00:27
Now, electric field at point p due to q1 is e1 which is equal to k multiplied by q1 divided by r square multiplied by cos 30 degree.
01:07
Now let's mark it as equation 1.
01:08
And, electric field at point p due to q2 is e2 which is equal to k multiplied by q2 divided by r square multiplied by cos 30 degrees.
01:47
Now let's mark it as equation 2.
01:50
So, total electric field which is being denoted by e equal to e1 plus e2 which is equal to k divided by r square multiplied by q1 cos 30 degree plus q2 cos 30 degree.
02:32
So now putting the values of the variables 9 multiplied by 10 raised to power 9 divided by 3 square multiplied by 3 multiplied by 10 raised to power minus 6 multiplied by 0 .866 plus 3 multiplied by 10 raised to power minus 6 multiplied by 0 .866.
03:10
So after simplifying this we get the value as 5 .196 multiplied by 10 raised to power 3 newton per coulomb which is the required answer of question number 1.
03:28
Now for question number 2 the required diagram is here is the charge q1 which is equal to plus 2 microcoulomb and this is the charge q2 which is equal to minus 4 microcoulomb.
04:02
Now this is the point p.
04:03
Now the direction of electric field due to q1 will be in the right direction and the electric field due to the charge q2 will also be in the right direction which is the required answer of question number 2.
04:25
Now for question number 3 drawing a diagram first this is the charge plus q this is the charge minus q this is the separation.
04:49
Now this distance is x and this distance is also x and this distance is r and this distance is also r.
05:11
So both of these angles are theta as they are isosceles and the coordinates are minus x comma 0 and this coordinate is x comma 0.
05:27
Now first of all at this point let's say it is p.
05:35
Now let's mark this charge as number 1 and this charge as number.
05:49
So the electric field at point p due to the charge 1 will be in this direction opposite and the electric field due to minus q charge will be in this direction.
06:11
So now resolving it into components we have this angle will be theta and this angle will also be theta...