25) Find Fz xa5 = 410.8352
26) Find FiX> 3 51 = A) 0.0341
27) Let XeEx/n be a sample mean Xsll drawn from Dr; Dai < distribution with u ~EX] 50ud ~tndurd deviation 0.5. Estimate the probability of the sample mean between 476 and 540, F[40 < X < 50] = A) 0.074 B) 0.499 C) 0.12 D) 0.452
28) Score df ACT exam X follows a Normal Distribution with p = FX] 25 5 and standard deviation 0. Find X-Score Z-Score = 15 A) 26 B) 27.025 C) 30
29) In Problems through 31, given the following information on Hypothesis Test:
29) Dr. Dai claims μ = 173 cm and Sample data sXe [X: X2 ~ X3ok with Ex 6200 cm and sample standard deviation Given = 10. Identify your Hypothesis with claim A) Ho: μ < 173; Ha: μ > 173 (claim) B) Ho: μ = 173 (claim); Ha: μ ≠173 C) Ho: μ = 173; Ha: μ > 173 (claim) D) Ho: μ ≠173 (claim); Ha: μ = 173
30) Find the Test Statistic A) Z = 1.2 B) Z = 2 C) Z = 2.4
30) Make decision on Claim A) Reject Claim μ < 173 B) Reject Claim μ > 173 C) Reject Claim μ = 173 D) Accept Claim μ = 173
31) In Problems through 3, given the following information:
31) Random sample of the circumference of 61 pumpkins M1.X2 Xoll with sample variance 80. Use the level of significance 0.05 to test the claim that the standard deviation of circumference of all pumpkins is less than 8 cm (that is, σ < 8). Identify Hypothesis with claim A) Ho: σ > 8 (Claim) B) Ho: σ = 8; Ha: σ < 8 C) Ho: σ < 8 (Claim) D) Ho: σ ≠8; Ha: σ < 8 (Claim)
32) Find Test Statistic A) 8 B) 75 C) 70 D) 65
32) Make Decision A) Reject Claim: σ > 8 B) Reject Claim: σ = 80 C) Accept Claim: σ < 8 D) Accept Claim: σ ≠80