Question

e two ropes seen in (Figure 1) are used to lower a 255 kg piano 5.10 m from a second-story window to the ground igure 1830 N 60° < 1 of 1 > 1295 N 45° Term 1: Correct answer is shown. Your answer 12750 J was either rounded differently or used a different number of significant figures than required for this part. Term 2: Correct answer is shown. Your answer -8082.6 J was either rounded differently or used a different number of significant figures than required for this part. Term 3: Correct answer is shown. Your answer -4670 J was either rounded differently or used a different number of significant figures than required for this part. SOLVE Model the piano as a particle and use $W = \vec{F} \cdot \Delta \vec{r}$, where $W$ is the work done by the force $\vec{F}$ through the displacement $\Delta \vec{r}$ For the force $\vec{F_C}$: $W = \vec{F} \cdot \Delta \vec{r} = F_C \cdot \Delta r = (F_C)(\Delta r) \cos(0^\circ) = (255 \text{ kg}) (9.81 \text{ m/s}^2) (5.10 \text{ m}) (1.00) = 1.3 \times 10^4 \text{ J}$ For the tension $\vec{T_1}$: $W = \vec{F} \cdot \Delta \vec{r} = T_1 \cdot \Delta r = (T_1)(\Delta r) \cos(150^\circ) = (1830 \text{ N}) (5.10 \text{ m}) (-0.8660) = -8100 \text{ J}$ For the tension $\vec{T_2}$: $W = \vec{F} \cdot \Delta \vec{r} = T_2 \cdot \Delta r = (T_2)(\Delta r) \cos(135^\circ) = (1295 \text{ N}) (5.10 \text{ m}) (-0.7071) = -4700 \text{ J}$ 2500 N $F_G$ Provide Feedback Next >

          e two ropes seen in (Figure 1) are used to lower a
255 kg piano 5.10 m from a second-story window to the
ground
igure
1830 N
60°
< 1 of 1 >
1295 N
45°
Term 1: Correct answer is shown. Your answer 12750 J was either rounded differently or used a different number of significant
figures than required for this part.
Term 2: Correct answer is shown. Your answer -8082.6 J was either rounded differently or used a different number of significant
figures than required for this part.
Term 3: Correct answer is shown. Your answer -4670 J was either rounded differently or used a different number of significant
figures than required for this part.
SOLVE Model the piano as a particle and use $W = \vec{F} \cdot \Delta \vec{r}$, where $W$ is the work done by the force $\vec{F}$ through the displacement
$\Delta \vec{r}$
For the force $\vec{F_C}$:
$W = \vec{F} \cdot \Delta \vec{r} = F_C \cdot \Delta r = (F_C)(\Delta r) \cos(0^\circ) = (255 \text{ kg}) (9.81 \text{ m/s}^2) (5.10 \text{ m}) (1.00) = 1.3 \times 10^4 \text{ J}$ 
For the tension $\vec{T_1}$:
$W = \vec{F} \cdot \Delta \vec{r} = T_1 \cdot \Delta r = (T_1)(\Delta r) \cos(150^\circ) = (1830 \text{ N}) (5.10 \text{ m}) (-0.8660) = -8100 \text{ J}$
For the tension $\vec{T_2}$:
$W = \vec{F} \cdot \Delta \vec{r} = T_2 \cdot \Delta r = (T_2)(\Delta r) \cos(135^\circ) = (1295 \text{ N}) (5.10 \text{ m}) (-0.7071) = -4700 \text{ J}$
2500 N
$F_G$
Provide Feedback
Next >

e two ropes seen in (Figure 1) are used to lower a
255 kg piano 5.10 m from a second-story window to the
ground
igure
1830 N
60°
< 1 of 1 >
1295 N
45°
Term 1: Correct answer is shown. Your answer 12750 J was either rounded differently or used a different number of significant
figures than required for this part.
Term 2: Correct answer is shown. Your answer -8082.6 J was either rounded differently or used a different number of significant
figures than required for this part.
Term 3: Correct answer is shown. Your answer -4670 J was either rounded differently or used a different number of significant
figures than required for this part.
SOLVE Model the piano as a particle and use W = F⃗·Δr⃗, where W is the work done by the force F⃗ through the displacement
Δr⃗
For the force F⃗C⃗:
W = F⃗·Δr⃗ = FC ·Δ r = (FC)(Δ r) cos(0^∘) = (255 kg) (9.81 m/s^2) (5.10 m) (1.00) = 1.3 × 10^4 J
For the tension T⃗1⃗:
W = F⃗·Δr⃗ = T1 ·Δ r = (T1)(Δ r) cos(150^∘) = (1830 N) (5.10 m) (-0.8660) = -8100 J
For the tension T⃗2⃗:
W = F⃗·Δr⃗ = T2 ·Δ r = (T2)(Δ r) cos(135^∘) = (1295 N) (5.10 m) (-0.7071) = -4700 J
2500 N
FG
Provide Feedback
Next >

Added by Edward L.

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