00:01
So i'm going to do this slightly out of order because if we answer the second part, then we actually get our answer for the first one.
00:09
Now, if we wanted to look at the limit of the sequence here, so the limit has an approach is infinity.
00:21
We could just go ahead and try to apply it directly, and we'd end up with infinity over something going to negative infinity, which that's one of the ways to know to use lopatose rule.
00:32
But in this case, since this is a rational function, we can also just divide by the largest power in the denominator, where it's going to be 1 over n in both.
00:41
And if we do that, we would know the limit as an approach to infinity of 7 over, so that would be negative 2, and then plus 11 over n.
00:52
And now notice if we apply the limit, then 7 just goes to 7, negative 2 goes to negative 2, and then 11 over n goes to 0.
01:00
So that is just going to be equal to 7 over negative 2...