00:01
Hi, i'm david and i'm here to help you answer your question.
00:04
Now let me bring up your question here.
00:06
In this question here we're given the probability distribution under x and the corresponding probability and here we will need to find the meaner standard division under x.
00:18
X can tell the value of the 0, 1, 2, 3, 4 and 6.
00:25
The probability of x it will be, the first one will be the 0 .0.
00:31
028 second going to be the 0 .1115 then 0 .3 72 0 .154 and then 0 .1107 .0 .1.
00:53
Oh sorry this one will be 5 here.
00:55
Sorry for that.
00:57
And then the next one will be the 0 .029.
01:01
And the question asks one is the missing value for the probability.
01:06
We know that the total probability must equal to 1.
01:10
So therefore the value we're looking for here.
01:14
Every condition will be some y.
01:17
So why must equal to the 1 minus everything.
01:21
So minus 0 .0 .015, minus 0 .3 .72.
01:28
Minus 0 .154, minus 0 .107, minus 0 .29.
01:36
And if we compare it, 1 minus 1 .0208, minus 1 .15, we get equal to the y here, it will equal to the 0 .195.
01:57
And that's going to be the answer for the first part.
02:01
The question, next one, we will need to find the mean and standard division.
02:05
To find the mean, first, i will need to compute the x -time.
02:07
Proper by predictor x...