A 200-kg crate is to be supported by the rope-and-pulley...

Name: A 200-kg crate is to be supported by the rope-and-pulley arrangement shown. Determine the magnitude and direction of the force P that must be exerted on the free end of the rope to maintain equilibrium. (Hint: The tension in the rope is the same on each side of a simple pulley. This can be proved by the methods of Chap. 4.)
Uploaded: 2021-11-08T00:56:56-08:00
Duration: 5 min 27 s
Channel: Christopher Dzorkpata
Description: A 200-kg crate is to be supported by the rope-and-pulley arrangement shown. Determine the magnitude and direction of the force P that must be exerted on the free end of the rope to maintain equilibrium. (Hint: The tension in the rope is the same on each side of a simple pulley. This can be proved by the methods of Chap. 4.)

A 200-kg crate is to be supported by the rope-and-pulley arrangement shown. Determine the magnitude and direction of the force P that must be exerted on the free end of the rope to maintain equilibrium. (Hint: The tension in the rope is the same on each side of a simple pulley. This can be proved by the methods of Chap. 4.)

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Transcript

0:00 Hello.

00:02 So this is going to be a free body diagram representing what is going on.

00:10 It's going to be supposed to be alpha.

00:14 So i'm trying to find the body and the value of p.

00:19 So we can do some geometry here.

00:23 So this is alpha and this is 90 minus alpha.

00:32 We're going to make this side also alpha.

00:34 So here we can say that an alpha is going to be equal to opposite which is this side which is also 2 .4 over adjacent which is 0 .75.

00:58 So you can find alpha.

01:03 Because alpha is going to be equal to the inverse of 2 .4 over 0 .75.

01:18 So you have a time universe of 5.

01:25 The value of alpha, the end of there is 72 point.

01:36 Let's say 6 degrees now because this is an equilibrium with and i also note that i have 2 t here because they were we got two ropes initially right we got two ropes like that and the tension in the same direction so t t t you know add up to the two t okay so i have two t so now we need to look at the vertical and the horizontal component of these forces right so, let's look at the horizontal component.

02:21 Horizonal.

02:28 So this angle here is also going to be alpha.

02:35 So we can say that for the horizontal, you can say that 2t, close alpha, is going to be equal to p cause alpha for the vertical...

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