1. A new trail leads a hiker down a path which winds 4 km...

1. A new trail leads a hiker down a path which winds 4 km due east, 6 km north, 2 km east, and 3 km south. What was the total distance traveled? What was the total displacement? Relative to the start of the trail, what was the direction of the total displacement vector? (3pt) 2. If the hiker in the previous problem completed the entire trail in 5 hours, what was the average speed of the hiker? What was the magnitude of the average velocity? (3pt) 3. At the instant of take-off, a long jumper has a forward velocity of 30 m/s and a vertical velocity of 22 m/s. Find the angle of the take-off (relative to the horizontal), and the magnitude of his take-off velocity. Without air resistance, how high and how long can he jump? (4pt)

Transcript

00:01 Hi, here out of so many different questions asked in this given problem, i am solving only first three and the first one which is marked as question 4.

00:13 In this, the distance between the two cities that is given as s is equal to 150 km.

00:37 Time taken to go from one city to another that is t1 is equal to 2 .5 hours and in return trip time taken is t2 is equal to 2 .0 hours in the first part of this problem average is while moving while going from one city to another that is v1 is equal to speed is equal to distance divided by time and it is calculated to be equal to 60 km per hour one of the answer for this first part of the problem similarly average is speed of the return journey, return trip, that is v2 is equal to distance will be same 150 kilometers divided by 2 hours.

02:40 So this v2 is calculated to be equal to 75 km per hour.

02:49 Second answer for the first part of this given problem here.

02:54 Now in the second part of the problem, here we have to find average speed of the entire trip, the total trip.

03:14 That will be given by the total distance that is 150 plus 150 km, divided by total time which is 2 .5 plus 2 .0 hours.

03:28 And it is calculated to be equal to 66 .7 kilometers per hour.

03:36 Answer for the second part of this question number 14 over here then in the next one and that is question number 15 distance traveled by the senior citizen round the mall that is s is equal to 0 .30 kilometer or it will be 300 meter and time taken to cover it t is equal to 10 minutes or we can say this is multiplied by 60 that will be 600 seconds.

04:34 In the first part of the problem, average speed of the senior citizen, speed v is equal to total distance 300 meters divided by total times 600 seconds...

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