00:01
Hello students to answer the question number, a, here lambda is equal to 4 and x follows the poison distribution of lambda equal to 4.
00:15
The p m of half, poison distribution is p of x equal to x which is e power minus lambda, lambda power x divided by x factorial.
00:28
For the first subpart, 1 is p of x equal to 0, which is c power minus 4, 4 power 0 divided by 0 factorial, we get 0 .01 a3.
00:43
Then for the second subpart, p of x less than or equal to 2.
00:48
That is p of x equal to 0 plus p of x equal to 1 plus p of x equal to 2.
00:56
Therefore, sum of x equal to 0 to 2, e power minus 4, 4 power x divided by x factorial, we get 0 .2381.
01:09
Then, for the third subpart, p of x greater than or equal to 4, which is 1 minus p of x less than 4, that is 1 minus p of x, p of x equal to 2 plus p of x equal to 3, which is 1 minus sum of x equal to 0 to 3, 3 power minus 4, 4 power x divided by x factorial.
01:41
We get our answer as 0 .5 -665.
01:49
Then 4 to support, p of 2 less than x less than 5, which is equal to sum of x equal to 2 to 5.
01:58
E power minus 4, 4 power x divided by x factorial...