00:01
Hello.
00:03
So we have here a new box 5.
00:10
A division of 5.
00:14
Two individuals are selected at random.
00:17
We want to find the probability that at least one of them has a height over 170.
00:24
So here what we need to do first is to find the probability a height more than 170.
00:35
So for normal distribution, we have x minus u over standard division greater than 170, 165.
00:45
X5 divided by 5 this is z greater than that's going to be 1 so we're going to have this is the same as probability of z nether than and go to minus 1 so we check the z table for negative 1 .15 is 6 6 okay now we have the probability of having a height 1 and 170 we can find the probability that at least one of them so that's greater than or equal to 1 is the probability that x equals 1 plus probability that x equals 2 right because our sample size is 2 so here we use the binomial distribution which is n combination x times p to the x x q to the n minus x where q equals 1 minus p so there are 1 minus 0 .15 8 6 6 6.
02:30
That's going to be 0 .84014.
02:36
0 .841 .3 .4.
02:42
So now the probability, so we do for x equals 1.
02:45
So we have 2, combination 1, plus n is 2, times p...