00:01
In this question according to the diagram.
00:02
So now you can see the diagram.
00:03
That's point a, point b and point c, and this length is 5 .12 fit and 6x1 and x2.
00:10
Let a .y and b .y be the vertical axis at a and b respectively.
00:17
So sigma m at b is equal to 0.
00:23
So, ay into 12 plus 1 upon 2 into 2 into 6 into 6 upon 3, 6 upon 3 minus 2 into 12 into 12 1 is equal to 0.
00:42
So, a, y is equal to 11k.
00:47
And for ab, for ab 0 is less than equal to x1 is less than equal to x1 is less than equal.
00:55
To 12.
00:56
So m and x1 is equal to a y, a y x1 minus 2 x1 into x1 upon 2 is equal to 11 x1 minus x1 square.
01:11
And for c b, for c b, m and x2 is equal to minus 1 upon 2 into 2 into x2 upon 3 and m and x2 is equal to minus x2 whole cube upon 18 and after that removing external load and assuming unit movement at c so sigma m and b is equal to 0 so a y into 12 a y into 12 plus 1 is equal to 0 so, ay is equal to minus 1 upon 12 and after that for ab, for ab, m x1 is equal to a .y x1 is equal to minus x1 upon 12.
02:16
And for c .b, m at x2 is equal to minus 1.
02:23
And now slope at c.
02:25
Now slope at c...