00:01
Given that sigma x is equal to minus 25 ksi and sigma xy is equal to tau xy is equal to 10 ksi.
00:15
The principal stress sigma 1, sigma 2 are given by principal stresses sigma 1 and sigma 2 are given by sigma 1, 2 is equal to sigma x plus sigma y divided by 2 plus or minus root of sigma x minus sigma y divided by 2.
00:51
2 the whole square plus tau x y square and we can write sigma 1 2 is equal to minus 25 plus 0 divided by 2 plus or minus root of minus 25 minus 0 divided by 2 whole square plus 10 square.
01:17
That is sigma 1 2 is equal to minus 12 .5 plus or minus 16.
01:23
Sigma 1 is equal to 3 .5 ksi and sigma 2 is equal to minus 28 .507 ksi.
01:35
Now orientation of orientation of of principal stresses, principal stresses theta p1 and theta p2 is given by tan 2 theta p is equal to 2xy divided by sigma x minus sigma y divided by 2 which is equal to 10 divided by minus 25 minus 0 by 2 which is equal to 20 by minus 25.
02:21
So we can write 2 theta p is equal to minus 38 .66 and theta p is equal to theta p1 theta p2 is equal to minus 19 .33 degree and 70 .67 degree.
02:44
So we can write theta p1 is equal to minus 19 .33 degree and theta p2 is equal to 70 .67 degree.
02:57
Now let's find the maximum in plane, maximum in plane shear stress, tau max.
03:16
We can write tau max is equal to root of sigma x minus sigma y by 2 the whole square plus tau x y square...