Problem S1. (8 points) I was changing the tire on my car and was having a hard time getting one of the bolts off: I was frustrated, but then I remembered I could use some good ole calculus to figure out how much force I need to apply to the wrench to get the bolt to move! When a force is applied to the wrench, a related force is applied to the bolt. These forces will put the wrench and the bolt
is the distance from the center of the bolt to where the force is applied. The bolts on my car have a diameter of 10 millimeters and I chose my longest wrench for the job, which is 300 millimeters long. Luckily my wrench has a nice grip 3/4 of the way from the part that fits around the bolt for easy use. I remembered that if the sum of the torque on the wrench, Ti, and the torque of the bolt, T2, is 0. then the bolt will not move. The longer I apply the force on the wrench, the more fatigued I get, and so the rate at which I am applying force to the wrench decreases, in fact the rate at which the force applied to the wrench is decreasing at 3/5 Newtons pcr second (N/s). At what rate is the force on thc bolt changing when I am applying 40 N to the wrench and nothing is moving yet? A picture has been included for you. Remember to state your answer with units as a statement.