Prove that W = {(2s + 4t, 28, 28 - 3t, 5t) | s, t ∈ R} is a vector subspace of R^4 by using the Subspace Test. Then, identify two vectors that span W.
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Step 1
Check if the zero vector is in W: Let s = 0 and t = 0, then the vector is (0, 28, 28, 0), which is not the zero vector. Therefore, W is not a vector subspace of R4. Since W is not a vector subspace of R4, there is no need to check for closure under addition and Show more…
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