Q1) Answer the following: Find y' (3 Marks) Y = Sin(3x)
Added by Martin A.
Step 1
The derivative of the outer function (Stin3x) is simply 1, and the derivative of the inner function (3x) is 3. So, we have: y' = 1 * 3cos(3x) Simplifying this expression, we get: y' = 3cos(3x) Show more…
Show all steps
Close
Your feedback will help us improve your experience
Rylie Howey and 99 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
find $y^{\prime}$. $y=\sin \frac{3}{x}$
More About Derivatives
The Chain Rule
Find $\frac{d y}{d x}$ in the following: $$ 2 x+3 y=\sin y $$
Continuity and Differentiability
Differentiability
find $d y / d x.$ \begin{equation}3+\sin y=y-x^{3}\end{equation}
Transcendental Functions
Exponential Functions
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD