Quadratic Function Concavity Vertex f (x) = x$^2$ - 5
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In this case, the given function is f(x) = x - 5. We can rewrite it in the general form by adding a coefficient of 0 for the x^2 term and a coefficient of 1 for the x term: f(x) = 0x^2 + 1x - 5 Now we can see that a = 0, b = 1, and c = -5. The concavity of a Show more…
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