Question

Solve $6\cos(2x) = 6\cos^2(x) - 4$ for all solutions $0 \le x < 2\pi$. Give your answers accurate to at least 2 decimal places and in a list separated by commas.

          Solve $6\cos(2x) = 6\cos^2(x) - 4$ for all solutions $0 \le x < 2\pi$.
Give your answers accurate to at least 2 decimal places and in a list separated by commas.

Solve 6cos(2x) = 6cos^2(x) - 4 for all solutions 0 ≤ x < 2π.
Give your answers accurate to at least 2 decimal places and in a list separated by commas.

Added by Alexander M.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Andrew Noble

Step 1

First, we need to use the identity cos(2θ) = 2cos^2(θ) - 1 to rewrite the equation as: 6cos(2θ) - 6cos(θ) = 1 Show more…

Show all steps

Thanks for your feedback!

Text: Question 10 0/1 pt 02 299 Details Score on last try: 0 of . pts. See Details for more Get similar question You can retry this question below Solve 6 cos(21) 6 cos? (1) for all solutions SI< %T. Give your answers accurate to at least 2 decimal places and list separated by commas. Question Help: Video Post to (0tUm Submit Question