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Question 16 Refer to Question 15 The following results are for independent random samples taken from two populations Sample Size Sample Mean Sample Standard Deviation Sample1 Sample2 n=15 n=12 =29.7 =34.1 s=10.2 S=11.8 second population. Assume the two population variances are equal. Find a 95% confidence interval for the difference in means. Select the correct answer. Oi. Use sp=√(10.2^2/15+11.8^2/12)=10.933. Compute 29.7-34.1±2.060x10.933=-4.422.52. The interval is -26.92, 18.12. Oii. Use sp=√((10.2^2+11.8^2)/27)=3.177. Compute 29.7-34.1±2.060x3.177=-4.42.53. The interval is -6.93, 1.87. Oji. Use sp=√(10.2^2/15+11.8^2/12)=10.933. Compute 29.7-34.1±2.060x10.933=-4.48.72. The interval is -13.12, 4.32. Oiv. Use sp=√(10.2^2/15+11.8^2/12)=10.933. Compute 29.7-34.1±1.678x10.933=-4.47.11. The interval is (-11.51, 2.71).

Name: question 16 refer to question 15 the following results are for independent random samples taken from two populations sample size sample mean sample standard deviation sample1 sample2 n15 n12 81413
Uploaded: 2023-01-16T03:22:41-08:00
Duration: 2 min 45 s
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Description: question 16 refer to question 15 the following results are for independent random samples taken from two populations sample size sample mean sample standard deviation sample1 sample2 n15 n12 81413

          Question 16 Refer to Question 15 The following results are for independent random samples taken from two populations
Sample Size
Sample Mean
Sample Standard Deviation
Sample1 Sample2
n=15 n=12
=29.7 =34.1
s=10.2 S=11.8
second population. Assume the two population variances are equal. Find a 95% confidence interval for the difference in means.
Select the correct answer.
Oi. Use sp=√(10.2^2/15+11.8^2/12)=10.933. Compute 29.7-34.1±2.060x10.933=-4.422.52. 
The interval is -26.92, 18.12.
Oii. Use sp=√((10.2^2+11.8^2)/27)=3.177. Compute 29.7-34.1±2.060x3.177=-4.42.53. 
The interval is -6.93, 1.87.
Oji. Use sp=√(10.2^2/15+11.8^2/12)=10.933. Compute 29.7-34.1±2.060x10.933=-4.48.72. 
The interval is -13.12, 4.32.
Oiv. Use sp=√(10.2^2/15+11.8^2/12)=10.933. Compute 29.7-34.1±1.678x10.933=-4.47.11. 
The interval is (-11.51, 2.71).

question 16 refer to question 15 the following results are for independent random samples taken from two populations sample size sample mean sample standard deviation sample1 sample2 n15 n12 81413

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