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Question 18 5 pts As part of a dietary-instruction program, ten 25-34-year-old males adopted a vegetarian diet for one month. While on the diet, the average daily intake of linoleic acid was 13 g with standard deviation 4. We want to test whether the intake of linoleic acid in this group is lower than that in the general population where µ=15. What is the correct null (HO) and alternate (H1) hypotheses? ? HO: ? > 15 and H1: ? < 15 ? HO: ? > 15 and H1: ? = 15 HO: ? = 15 and H1: ? < 15 ? HO: ? = 15 and H1: ? = 15 or ? > 15 Question 19 7 pts From question 18, What is the correct test statistics? O $t_0 = \frac{13 - 15}{\frac{4}{\sqrt{10}}}$ O $t_0 = \frac{13 - 15}{\sqrt{10}}$ O $t_0 = \frac{13 - 15}{\frac{4}{10}}$ O $z_0 = \frac{13 - 15}{\frac{4}{\sqrt{10}}}$

          Question 18
5 pts
As part of a dietary-instruction program, ten 25-34-year-old males adopted a vegetarian diet
for one month. While on the diet, the average daily intake of linoleic acid was 13 g with
standard deviation 4. We want to test whether the intake of linoleic acid in this group is lower
than that in the general population where µ=15. What is the correct null (HO) and alternate
(H1) hypotheses?
? HO: ? > 15 and H1: ? < 15
? HO: ? > 15 and H1: ? = 15
HO: ? = 15 and H1: ? < 15
? HO: ? = 15 and H1: ? = 15 or ? > 15
Question 19
7 pts
From question 18, What is the correct test statistics?
O $t_0 = \frac{13 - 15}{\frac{4}{\sqrt{10}}}$
O $t_0 = \frac{13 - 15}{\sqrt{10}}$
O $t_0 = \frac{13 - 15}{\frac{4}{10}}$
O $z_0 = \frac{13 - 15}{\frac{4}{\sqrt{10}}}$

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Question 18
5 pts
As part of a dietary-instruction program, ten 25-34-year-old males adopted a vegetarian diet
for one month. While on the diet, the average daily intake of linoleic acid was 13 g with
standard deviation 4. We want to test whether the intake of linoleic acid in this group is lower
than that in the general population where µ=15. What is the correct null (HO) and alternate
(H1) hypotheses?
? HO: ? > 15 and H1: ? < 15
? HO: ? > 15 and H1: ? = 15
HO: ? = 15 and H1: ? < 15
? HO: ? = 15 and H1: ? = 15 or ? > 15
Question 19
7 pts
From question 18, What is the correct test statistics?
O t0 = (13 - 15)/((4)/(√(10)))
O t0 = (13 - 15)/(√(10))
O t0 = (13 - 15)/((4)/(10))
O z0 = (13 - 15)/((4)/(√(10)))

Added by Marcos M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Kari Hasz

09/15/2022

Step 1

Step 1: Calculate the test statistic using the formula: t = (x̄ - μ) / (s / √n) where x̄ is the sample mean (13), μ is the population mean (15), s is the standard deviation (4), and n is the sample size (10). Show more…

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Question 18 5 pts As part of a dietary-instruction program, ten 25-34-year-old males adopted a vegetarian diet for one month. While on the diet, the average daily intake of linoleic acid was 13g with standard deviation 4. We want to test whether the intake of linoleic acid in this group is lower than that in the general population where mu =15. What is the correct null (HO) and alternate (H1) hypotheses? H0:mu >15 and H1:mu <15 H0:mu >15 and H1:mu =15 xH0:mu =15 and H1:mu <15 ANSWER H0:mu =15 and H1:mu =15 or mu >15 Question 19 7 pts From question 18 , What is the correct test statistics? t_(0)=(13-15)/((1)/(sqrt(10))) t_(0)=(13-15)/((16)/(sqrt(10))) t_(0)=(13-15)/((1)/(14)) t_(0)=(13-15)/((16)/(16)) LOOKING FOR HELP WITH #19 Question 18 5 pts As part of a dietary-instruction program, ten 25-34-year-old males adopted a vegetarian diet for one month.While on the diet,the average daily intake of linoleic acid was 13 g with standard deviation 4.We want to test whether the intake of linoleic acid in this group is lower than that in the general population where =15.What is the correct null (HO) and alternate (H1)hypotheses? OHO>15and H1<15 OHO:>15and H1:=15 HO=15andH1<15 HO=15andH1:=15or>15 Question 19 7pts From question 18,What is the correct test statistics? 1315 Ota Oto

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