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Question2: Score 0/1 Consider the three points A(1, 3, -1), B(4, 1, 3) and C(-24, 17, -29). From the fact that the vector \overrightarrow{AB} a scalar multiple of the vector \overrightarrow{BC}, we deduce that the three points A, B and C are

          Question2: Score 0/1
Consider the three points A(1, 3, -1), B(4, 1, 3) and C(-24, 17, -29).
From the fact that the vector \overrightarrow{AB}
a scalar multiple of the vector \overrightarrow{BC}, we deduce that the three points A, B and C are

Question2: Score 0/1
Consider the three points A(1, 3, -1), B(4, 1, 3) and C(-24, 17, -29).
From the fact that the vector AB
a scalar multiple of the vector BC, we deduce that the three points A, B and C are

Added by Mark B.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Madhur L

02/14/2023

Step 1

To find the vector AB, we subtract the coordinates of point A from the coordinates of point B: AB = B - A = (4, 1, 3) - (1, 3, -1) = (3, -2, 4). To find the vector BC, we subtract the coordinates of point B from the coordinates of point C: BC = C - B = (-24, 17, Show more…

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Question 2: Score 0/1 Consider the three points A(1, 3, -1), B(4, 1, 3), and C(-24, 17, -29). From the fact that the vector AB is not a scalar multiple of the vector BC, we deduce that the three points A, B, and C are not collinear. Your response: Correct Correct response: not collinear Auto graded Grade: 0/1.0