Step 1:
The given differential equation is:
$\frac{d^2y}{dt^2} + 8\frac{dy}{dt} + 20y = 300\sin 4t$
The characteristic equation is:
$m^2 + 8m + 20 = 0$
Using the quadratic formula, we get:
$m = \frac{-8 \pm \sqrt{64 - 4(20)}}{2} = \frac{-8 \pm \sqrt{-16}}{2} = -4
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