00:01
In this question we have been given that there are a population size n is equals to 6 with the units given as 2, 4, 6, 8, 10 and 12.
00:17
These are the units and out of which sample size n equals to 5 are to be selected based on simple random sampling without replacement.
00:27
Correct? we need to prove that the mean of the sample is unbiased estimator of the population and then we have to find out what is the mean and variance of the random variable.
00:41
So let us see how we are going to do this here.
00:45
So i will write here by without replacement there will be 6 c5 samples and this is equals to 6 only.
01:08
We will find sample and their corresponding means in the following table first then we proceed.
01:14
So this is the three column the first one it represents the sample number the second one is for the sample observation and the third column is for the sample mean.
01:31
Correct? denoted by xi.
01:35
So it is first, second, third.
01:38
We have total 6 samples and observations they can be in any order 4, 6, 8, 10, 12 or it can be 2, 6, 8, 10, 12.
01:50
Then we have 2, 4, 8, 10, 12.
01:56
Next we have 2, 4, 6, 10, 12.
01:59
Then 2, 4, 6, 8, 12 and finally we are having 2, 4, 6, 8 and 10 and sample mean it comes out to be 8 then it is 7 .6 mean we are just calculating for this observation and for the third one we have 7 .2 next one is given to be 6 .8 and then next is 6 .4 and last one gives you mean equals to 6...