00:01
So to solve this question, first of all, we will have to use the arrhenius equation.
00:04
Arrhenius equation stated, natural log k2 divided by k1 equals e8.
00:18
This is activation energy divided by r.
00:21
R is the idealized constant 1 divided by t1 minus 1 divided by t2.
00:32
So in this case, t1 is the initial boiling temperature, which is 100 degrees celsius.
00:41
T2 is the high attitude of boiling temperature, 95 .4, but you're going to have to convert them into kelvin first.
00:51
So say t1 is 100 plus 273, which is 373k.
01:05
T2 is 9.
01:07
Let's include the decimals, 15.
01:17
94 .5.
01:21
I'm sorry.
01:26
Plus 23 .3 .15.
01:29
This equals 368 .55k.
01:38
So, and we also know that ea, the activation energy is 400553k droop per more...