00:01
Hello students, in this question we have to find out charge, energy, as well as electric field of the capacitor.
00:18
In order to find out this, we can use the formula of the capacitance which is given as capacitance is equal to epsilon or a divided by d.
00:29
Epsilon entry is the constant value permittivity of free space which is written as this.
00:38
And area given is 0 .255 meter square substitute for that and separation between the plates is 4 .64 into 10 power minus 3.
00:51
By calculating this we get the capacitance value as 4 .86 into 10 rise to minus 10.
00:59
By using this we can calculate charge of the capacitor by using the formula q is equal to c into v, where capacitance substitute for that and voltage given 20 volts.
01:16
By calculating this we get charge of the capacitor as 9 .72 nano coolump, that is 10 power minus 9 coolum.
01:29
Now we have to calculate energy stored in capacitor for that we can use the formula u is equal to half c .v square...