00:02
Here we use mathematical induction to prove that sn is true for every positive integer n.
00:09
For that, we follow these steps here.
00:13
Part a we verify s1, and part b we write sk, in part b we write sk plus 1.
00:18
In part b, we write sk plus 1.
00:19
In part b, we write sk plus 1, and in part b we write a conclusion.
00:28
Based on steps a through d, the statement is sk.
00:33
N is 1 cube plus 2 cube plus 3 cube plus up to n -cube equals n squared times n plus 1 square over 4.
00:45
So what we have here on the left is the sum of the cubes of the first n natural numbers.
00:52
And we state that that sum is equal to n squared times n plus 1 squared over 4.
01:00
So in part a we're going to verify as 1.
01:03
When n equals 1, the left side of the sum, of the equality, sorry, is just the first term.
01:15
There is no sum at all, but only the first term, one cube.
01:21
And the right side is 1 square times 1 plus 1 square over 4.
01:29
So the left side is 1, which is 1 cube.
01:33
And on the right side, we have 1, which is 1 square.
01:36
Then times 2 squared over 4, that is 1 equal 1 times 4 over 4, that is 1 equal 4 over 4, that is 1 equal 1.
01:56
That is true.
01:58
And because this is true, we can say that s1 is true.
02:05
And so we have verified the statement for n equals 1, that is 1.
02:12
Now in part p we write the statement as k by replacing n by k in this general statement here above.
02:21
So we get 1 cube plus 2 cube plus 3 cube plus up to k cube equals k squared times k plus 1 square over 4.
02:37
That's the statement for n equals k.
02:41
Now for n equals k plus 1 that is s of k plus 1 is a statement that on the left we have the sum up to the cube of k plus 1 that is 1 q plus 2 q plus 3 q plus we know that we got a stop at k plus 1 cube but we know that before this term we have k cube which is this one here and on the right side we're going to have k plus 1 square times k plus 1 plus 1 square over 4.
03:22
Look that here we have k plus 1 instead of k here.
03:29
And that's the statement k plus 1.
03:33
Now in part d we are going to prove that if s k is true then sk plus 1 is true or any integer.
03:48
Or positive integer k...