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• Question 4 < > 3x\textsuperscript{2} + 20x + 25 Let f(x) = \frac{3x\textsuperscript{2} + 20x + 25}{3x\textsuperscript{2} - 5x - 2} This function has: 1) A y intercept at the point 2) x intercepts at the point(s) 3) Vertical asymptotes at x = Question Help: Video Calculator Submit Question

          • Question 4
< >
3x\textsuperscript{2} + 20x + 25
Let f(x) = \frac{3x\textsuperscript{2} + 20x + 25}{3x\textsuperscript{2} - 5x - 2}
This function has:
1) A y intercept at the point
2) x intercepts at the point(s)
3) Vertical asymptotes at x = 
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• Question 4
< >
3x2 + 20x + 25
Let f(x) = (3x2 + 20x + 25)/(3x2 - 5x - 2)
This function has:
1) A y intercept at the point
2) x intercepts at the point(s)
3) Vertical asymptotes at x = 
Question Help: Video
Calculator
Submit Question

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Question 4 Let f(x) = (3x^2 + 20x + 25) / (3x^2 - 5x - 2) This function has: A y-intercept at the point x-intercepts at the point(s) Vertical asymptotes at x =
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Transcript

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00:01 In this question, we are going to determine the x and y intercepts and asymptotes of the given rational function.
00:09 I would like to rewrite the numerator of the rational function.
00:15 All right.
00:29 Vertical asymptotes come from the denominator.
00:40 Factor and set each factor equal to zero.
00:45 So we have vertical asymptotes of x equal zero and and x equals negative 2.
01:02 To get the horizontal asymptote, you look at the leading terms.
01:09 Because they are the same degree, you think about the division...
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