Question 5 in a certain high school 11 of the students like...

Name: question 5 in a certain high school 11 of the students like math while 28 of the students like chemistry suppose we randomly choose a student from this high school denote pm event that the c 65762
Uploaded: 2023-01-18T04:44:47-08:00
Duration: 2 min 35 s
Channel: Sri K
Description: question 5 in a certain high school 11 of the students like math while 28 of the students like chemistry suppose we randomly choose a student from this high school denote pm event that the c 65762

Question 5 In a certain high school, 11% of the students like math, while 28% of the students like chemistry. Suppose we randomly choose a student from this high school. Denote: P(M)= event that the chosen student likes math P(C) = event that the chosen student likes chemistry p= probability that the chosen student likes both math and chemistry What should p be so that events P(M) and P(C) are independent? Create R variable p with the answer to this question. Do not round your answer. Make sure the decimal digits 3 and 4 are 1 and 9, respectively

Transcript

00:01 The question here is that it is given that as be the event of randomly selecting the college okay, so it is given that probability of s that is equivalent to 0 .4 this is given to a trend probability for the chemistry that is equivalent to 0 .3 this is for the stats and probability of s intersection c this is given to a 0 .2 so here the different parts are given so here the a part is that probability that a student has taken at least one of the two forces at least one we have to find the probability okay for the at least one so we have p s union c we have the formula that is equivalent to p of s plus p of c minus p s intersection c so this will be the formula with us clear so now where we are going to solve this out so putting this value of p s which is 0 .4 plus p c that is 0 .3 minus this is 0 .2 so so solving this out we get this earlier 0 .5 so here this p s union c that's what we have to calculate at least one or both can also be selected so this probability is equivalent to what 0 .5 now moving ahead for the b part in which it is asked to calculate the probability that a student has neither taken the stats or not the chemistry that is so we have the formula here that b h dash is intersection c dash that's what we have to calculate it this is equal to what p s union c and its whole dash so that means 1 minus b s union c solving this out this is 1 minus 0 .5 so value for this is equivalent to 0 .5 this will be the answer for the b5 now in the c part it is asked to calculate probability that the student has taken the stats okay it only equal stats that means only stats but not the chemistry that means we have to calculate the probability of s intersection c -dash that is equivalent to probability of s minus probability of s intersection solving this out so this is 0 .4 it is 0 .4 minus 0 .2 solving this value so we get this earlier 0 .2 so this will be the answer for the c -pire so here all the 3 -5 are answered over there for this given question...

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