Question 7 (1 point) Find the area of the triangle whose vertices are the points A = (3, 2, 0), B = (1, -2, 1) and c = (1,-1,-1). - sqrt{69} - 69 - frac{1}{2}sqrt{69} - sqrt{frac{69}{2}} - 2sqrt{69} - frac{69}{2}
Added by Brett G.
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AB = B - A = (1 - 3, -2 - 2, 1 - 0) = (-2, -4, 1) AC = C - A = (1 - 3, -1 - 2, -1 - 0) = (-2, -3, -1) Show more…
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