Question

Question number 29. Solve for x: $$6^{x-10} = 4$$ $$x = \log_6(6) + 10$$ $$x = \ln\left(\frac{2}{3}\right) + 10$$ $$x = \log_6(4) + 10$$ $$x = \log_6(4) - 10$$ $$x = \log_6(6) - 10$$ None of the above

Name: question number 29 solve for x 6x 10 4 x log66 10 x lnleftfrac23right 10 x log64 10 x log64 10 x log66 10 none of the above 78926
Uploaded: 2024-03-08T04:24:04-08:00
Duration: 1 min 2 s
Channel: Khushbu Rani
Description: question number 29 solve for x 6x 10 4 x log66 10 x lnleftfrac23right 10 x log64 10 x log64 10 x log66 10 none of the above 78926

          Question number 29.
Solve for x:
$$6^{x-10} = 4$$
$$x = \log_6(6) + 10$$
$$x = \ln\left(\frac{2}{3}\right) + 10$$
$$x = \log_6(4) + 10$$
$$x = \log_6(4) - 10$$
$$x = \log_6(6) - 10$$
None of the above

$question number 29 solve for x 6x 10 4 x log66 10 x lnleftfrac23right 10 x log64 10 x log64 10 x log66 10 none of the above 78926$

Added by Mark J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Khushbu Rani

03/08/2024

Step 1

To solve for x, we need to isolate x. Since x is in the exponent, we can use logarithms. We can take the logarithm with base 6 on both sides of the equation. Step 2: Take the logarithm with base 6 on both sides of the equation: $$\log_6(6^{x-10}) = Show more…

Show all steps

Thanks for your feedback!

Question number 29. Solve for x: $$6^{x-10} = 4$$ $$x = \log_6(6) + 10$$ $$x = \ln\left(\frac{2}{3}\right) + 10$$ $$x = \log_6(4) + 10$$ $$x = \log_6(4) - 10$$ $$x = \log_6(6) - 10$$ None of the above