Suppose that $||\vec{u}|| = 2$ and $||\vec{v}|| = 6$, and that $\vec{u} \cdot \vec{v} = -4$. Find the angle $\theta$ between the vector $\vec{u}$ and $\vec{v}$, rounded to the nearest degree.
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The dot product is given by the formula: i · V = |i| * |V| * cos(theta) where theta is the angle between the vectors i and V. Given that |i| = 2, |V| = 6, and i · V = -4, we can rearrange the formula to solve for cos(theta): cos(theta) = (i · V) / (|i| * Show more…
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