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Score before penalty on last attempt: 0.5 out of 2 Score on last attempt: 0 out of 2 Score in gradebook: 0.5 out of 2 Suppose a car passes a crosswalk while driving at a constant speed of 20 feet per second and continues driving at this constant speed. Let $t$ represent the number of seconds since the car passed the crosswalk and let $d$ represent the car's distance from the crosswalk (in feet). a. Suppose $t$ changes from $t = 3$ to $t = 5.2$ i. How much time has passed between $t = 3$ and $t = 5.2$? $\Delta t = 2.2$ seconds Preview ii. What was the change in the car's distance from the crosswalk (in feet) over this interval of time? $\Delta d = 55/2.2$ feet Preview iii. Over this interval of time, the change in the car's distance from the crosswalk in feet ($\Delta d$) is how many times as large as the change in the number of seconds since the car passed the crosswalk ($\Delta t$)? $\frac{\Delta d}{\Delta t} = $ Preview b. Over any interval of time, the car's change in distance from the crosswalk (in feet) is 25 times as large as the change in the number of seconds since the car passed the crosswalk. Submit Submission Error Question 6. Points available on this attempt: 0.8 of original 2 This is attempt 4 of 6. Score on last attempt: 0. Score in gradebook: 0.5

          Score before penalty on last attempt: 0.5 out of 2
Score on last attempt: 0 out of 2
Score in gradebook: 0.5 out of 2
Suppose a car passes a crosswalk while driving at a constant speed of 20 feet per second and continues driving at this constant speed. Let $t$ represent the number of seconds since the car passed the crosswalk and let $d$ represent the car's distance from the crosswalk (in feet).
a. Suppose $t$ changes from $t = 3$ to $t = 5.2$
i. How much time has passed between $t = 3$ and $t = 5.2$? 
$\Delta t = 2.2$ seconds Preview
ii. What was the change in the car's distance from the crosswalk (in feet) over this interval of time?
$\Delta d = 55/2.2$ feet Preview
iii. Over this interval of time, the change in the car's distance from the crosswalk in feet ($\Delta d$) is how many times as large as the change in the number of seconds since the car passed the crosswalk ($\Delta t$)?
$\frac{\Delta d}{\Delta t} = $ Preview
b. Over any interval of time, the car's change in distance from the crosswalk (in feet) is 25 times as large as the change in the number of seconds since the car passed the crosswalk.
Submit Submission Error
Question 6. Points available on this attempt: 0.8 of original 2
This is attempt 4 of 6.
Score on last attempt: 0. Score in gradebook: 0.5

Score before penalty on last attempt: 0.5 out of 2
Score on last attempt: 0 out of 2
Score in gradebook: 0.5 out of 2
Suppose a car passes a crosswalk while driving at a constant speed of 20 feet per second and continues driving at this constant speed. Let t represent the number of seconds since the car passed the crosswalk and let d represent the car's distance from the crosswalk (in feet).
a. Suppose t changes from t = 3 to t = 5.2
i. How much time has passed between t = 3 and t = 5.2?
Δ t = 2.2 seconds Preview
ii. What was the change in the car's distance from the crosswalk (in feet) over this interval of time?
Δ d = 55/2.2 feet Preview
iii. Over this interval of time, the change in the car's distance from the crosswalk in feet (Δ d) is how many times as large as the change in the number of seconds since the car passed the crosswalk (Δ t)?
(Δ d)/(Δ t) = Preview
b. Over any interval of time, the car's change in distance from the crosswalk (in feet) is 25 times as large as the change in the number of seconds since the car passed the crosswalk.
Submit Submission Error
Question 6. Points available on this attempt: 0.8 of original 2
This is attempt 4 of 6.
Score on last attempt: 0. Score in gradebook: 0.5

Added by Tonya G.

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