Required information three horizontal forces are applied to...

Name: required information three horizontal forces are applied to a vertical cast iron arm as shown in the figure p a 150 mm b 600 n 150 mm c 400 n 150 mm d when p 1000 n the force couple system r 37743
Uploaded: 2022-04-18T15:20:36-08:00
Duration: 7 min 44 s
Channel: Vishal Gupta
Description: required information three horizontal forces are applied to a vertical cast iron arm as shown in the figure p a 150 mm b 600 n 150 mm c 400 n 150 mm d when p 1000 n the force couple system r 37743

Required Information Three horizontal forces are applied to a vertical cast iron arm as shown in the figure. P A 150 mm B 600 N 150 mm C 400 N 150 mm D When $P = 1000 N$, the force-couple system reduces to a couple only. True or False True False

Transcript

00:01 Hi, here in this given problem first of all this is a vertical cast iron arm which is fixed at a horizontal surface.

00:13 It is riveted at this surface here at the topmost point a horizontal force p is being applied whose value keeps changing.

00:27 Then at the two points equidistant points this is point c at which a force of 400 newton is being applied towards left then this is the point b at which 600 newton is being applied and this is the topmost point a gap between these points as these are equity stands so this is 150 millimeter each now in the first part of the problem the value of this force unknown force this is given as 200 newton so first of all we have to find net horizontal force acting on this cast iron arm so net force will be given by f net is equal to total leftward forces 600 newton plus 400 newton minus rightward forces which is a single one 200 newton so it comes out to be equal to just 800 newton which will be acting towards left now to find the position of the application of this force means position of line of action of this force we use the concept that torque created by the net torque created by the three forces should be equal to that created by a single force which is the resultant means net force so we can see first of all we find the torque created by these three forces individually and then adding it and here it comes out to be equal to first of all torque created by 600 newton force this is 600 newton and torque about this point at the ground so this is 600 newton multiplied by 300 mm plus again counterclockwise torque created by 400 newton but multiplied by 150 millimeter only and then the force the torque created by this rightward force it will create a clockwise torque and that will be for p this is 200 newton and perpendicular distance that is in all 450 millimeter and this much torque net torque should be equal to that created by the net force net force this is 800 newton and we have to find its distance its position which is x suppose so we get the value of this x to be equal to for 600 into 300 it will be 1 8000000 plus 6000000 and minus 9000 0 0 0 divided by 800 so the position comes out to be equal to 187 .5 millimeter answer for the first part of the problem the two answers for the first part of the problem this was the first one f net and this it just found that is the second one now in the second part of the problem part b this time force p is given as 2 ,400 newton so first of all we find net force and the net force will be 2 ,400 newton towards right minus 1 ,600 plus 400 will be 1 ,000 1 ,000 newton towards left so the resultant will come out to be equal to 1 ,400 newton and that will be towards right.

05:34 Then again to find the location, to find out the position of this force, again we use the same concept...

Question

Required Information Three horizontal forces are applied to a vertical cast iron arm as shown in the figure. P A 150 mm B 600 N 150 mm C 400 N 150 mm D When $P = 1000 N$, the force-couple system reduces to a couple only. True or False True False

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