retail storet daily sales are normally distributed with meanp of 5300000 and stdevp of s50000 fi

Name: retail storet daily sales are normally distributed with meanp of 5300000 and stdevp of s50000 find the probability that if you randomly select day its sales are greater than 53120 hint since 67044
Uploaded: 2023-05-23T11:01:28-08:00
Duration: 2 min 34 s
Channel: Numerade
Description: retail storet daily sales are normally distributed with meanp of 5300000 and stdevp of s50000 find the probability that if you randomly select day its sales are greater than 53120 hint since 67044

In this question, we have been given to calculate the value of probability such that in the firs

Let's start by representing this information, this normal distribution on a bell curve. So we're

In the first question, the mean and the standard deviation is given. We have to find the probabi

Hi, I'm David and I'm here to have you on the question. Now let me pick up your question here. I

Here, the mean and standard deviation are given for type 1, type 2 and type 3. Therefore, for th

Question

Retail store daily sales are normally distributed with a mean (MEANP) of 53,000.00 and a standard deviation (STDEV.P) of 500.00. Find the probability that if you randomly select a day, its sales are greater than 53,120 (hint: since this problem uses all population values, this is actually a review of a chapter problem) (check figure: 40.52%). X - MEANP = 3120 STDEV.P = 500.00 Z = (X - MEANP) / STDEV.P = 120.00 / 500.00 = 0.24 The probability that a randomly selected day's sales are greater than 53,120 is 59.48%. If you randomly select 13 days, their mean daily sales are greater than 53,120.00 (with this problem, a sample is introduced; therefore it is indicative of a chapter problem) (check figure: 19.22%). STERR = STDEV.P / SQRT(13)

          Retail store daily sales are normally distributed with a mean (MEANP) of 53,000.00 and a standard deviation (STDEV.P) of 500.00. Find the probability that if you randomly select a day, its sales are greater than 53,120 (hint: since this problem uses all population values, this is actually a review of a chapter problem) (check figure: 40.52%).

    X - MEANP = 3120
    STDEV.P = 500.00
    Z = (X - MEANP) / STDEV.P = 120.00 / 500.00 = 0.24
    The probability that a randomly selected day's sales are greater than 53,120 is 59.48%.

    If you randomly select 13 days, their mean daily sales are greater than 53,120.00 (with this problem, a sample is introduced; therefore it is indicative of a chapter problem) (check figure: 19.22%).

    STERR = STDEV.P / SQRT(13)

retail storet daily sales are normally distributed with meanp of 5300000 and stdevp of s50000 find the probability that if you randomly select day its sales are greater than 53120 hint since 67044

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