Sales at a restaurant average $6,000 per day. The restaurant decided to introduce an advertising campaign to increase daily sales. To determine the effectiveness of the advertising campaign, a sample of 49 days of sales was taken. They found that the average daily sales were $6,300 per day. From past history, the restaurant knew that its population standard deviation is about $1,000. If the level of significance is 0.05, have sales increased as a result of the advertising campaign? Using the following hypothesis test, select one of the following answers below.
H0: µ ≤ 6,000
H1: µ > 6,000.
A) Fail to reject the null hypothesis.
B) Reject the null hypothesis and conclude the mean is higher than $6,000 per day.
C) Reject the null hypothesis and conclude the mean is lower than $6,000 per day.
D) Reject the null hypothesis and conclude that the mean is equal to $6,000 per day.
2. Corrected_text: The Iowa Department of Labor and Employment Security reported the state mean annual wage of $26,133. A test of wages by county can be conducted to see which counties have a mean annual wage that differs from the state mean.
A) Choose from below the null and alternate hypothesis that can be used to determine whether the sample data from a particular county support their conclusion that the population mean annual wage for the county differs from the state mean of $26,133.
1. H0: µ ≥ $26,133
H1: µ < $26,133
2. H0: µ = $26,133
H1: µ ≠$26,133
3. H0: µ < $26,133
H1: µ ≥ $26,133
4. H0: µ ≥ $26,133
H1: µ = $26,133
B) A sample of 550 people in Johnson County showed a sample mean annual wage of $25,457 and a sample standard deviation of $7,600. Compute the value of the test statistic: _____.
C) Using α = 0.05, what is your conclusion?
1. Reject H0
2. Fail to reject H0
Title_with_topic:
1. Hypothesis Testing for Sales Increase in a Restaurant
2. Hypothesis Testing for County Mean Annual Wages