00:01
Hello, two solid steel shafts are connected by the gear shown, a torque of magnitude t equals to 900 nm applied to the shaft a, b, knowing that the allowing sharing stress is 50 mpa and a share considering only stress due to the twisting, determine the required diameter here.
00:22
So as here, t of a, b is equal to t, which is equal to 1 ,500 nm here and two is equal to each, equals to 12 megapascal here and d b is equal to 70 mm or we can write it as here 0 .07m here and d c is equal to 200 mm or we can write it as here point 2m here so to find the diameter of the shaft ab and cd so as we know that the power is transmitted by the gear b is equal to the power of transmitted received by the gear c so we can write here p of b is equal to p of here seems p of b can be written as here t a in t of ab into distance r b which is equal to t of c into distance r c here so as here r is equals to here t of a b is into r b is equal to d b by two which is equal to t c into r c is equal to d c by two here so by simplifying this this one is 1 ,500 into 07 divided by 2 is equals to tc into 0 .02 divided by 2 is equal to tc into 0 .02 divided by 2 here.
01:32
So by simplifying this expression tc can be written as here 525 nm.
01:38
Now the finding of the diameter of each shaft according to the torsion equation since t by t is equal to by r which is equal to g theta divided by l here.
01:50
So by substituting value here, this one is j of ab divided by j of ab which is equal to toe divided by d ab divided by d ab divided by 2 here.
02:03
So by simplifying this expression here, t of a, b divided by 5 by 32 into d .a .b.
02:10
R.
02:10
To the power 4 here, which is equal to 2 divided by d .a .b divided by 2 here...