00:01
This question is about a father's age and his two children.
00:04
Right now equals 48.
00:06
The sum of the three ages equals 48.
00:09
Then the second statement says, if you double the sum of the two children's ages ten years in the future, so a plus ten and b plus ten doubled, will equal the father's age plus six, but the father has also aged ten years.
00:28
And then the third statement says, three times the older child's age plus 26 was the father's age when the second child was born.
00:41
So now, if i take what f equals and substitute it in to this equation for f and this equation for f.
00:53
So 3a plus 26 and then the rest of this one.
01:02
That's 4a plus b equals, and then if i subtract, oops, sorry, not x.
01:10
4a plus b and then subtract 26 from 48, you get 22.
01:18
Okay, we're gonna hold on to that for a minute.
01:21
Then we'll take this one and simplify.
01:24
So 2 times a plus b plus 20 equals, and then instead of f, i'm gonna put this in, and then simplify that a bit.
01:49
3a plus, and that comes out to be 42 over there.
01:56
Okay, then we'll simplify some more.
01:59
So if i bring the a over, this subtract the 2a, that leaves me with a over here...